Re: how do I do a literal string in the target of a regex?

On 10/29/22 14:28, ToddAndMargo via perl6-users wrote:
> On 10/29/22 13:07, Elizabeth Mattijsen wrote:
>  > $ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)'
>  >
> 
> Hi Elizabeth,
> 
> Thank you for the subst workaround!

I created a keep of the subst.  Got to
love Raku. 101 ways of doing everything!

• how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users