Re: how do I do a literal string in the target of a regex?

On 10/29/22 13:02, ToddAndMargo via perl6-users wrote:
> Hi All,
> 
> I am trying to change
> 
>       /
> 
> into
> 
>       \\\
> 
> This works:
> 
> 
> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\\\\\|;print $x 
> ~ "\n"'
> a\\\b\\\c\\\d
> 
> 
> But this does not:
> 
> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|Q[\\\]|;print $x 
> ~ "\n"'
> aQ[\]bQ[\]cQ[\]d
> 
> 
> How do I put a literal string in the
> target of a regex?
> 
> Many thanks,
> -T


The guys on the chat line made me write a
better description and in the process I
figured it out!

$ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|$(Q[\\\])|;print 
$x ~ "\n"'

a\\\b\\\c\\\d


I forgot the $() in the target!

• how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users