Re: how do I do a literal string in the target of a regex?

>> On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users <perl6-users@perl.org> wrote:
>>
>> Hi All,
>>
>> I am trying to change
>>
>>      /
>>
>> into
>>
>>      \\\
>>
>> This works:
>>
>>
>> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\\\\\|;print $x ~ "\n"'
>> a\\\b\\\c\\\d
>>
>>
>> But this does not:
>>
>> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|Q[\\\]|;print $x ~ "\n"'
>> aQ[\]bQ[\]cQ[\]d
>>
>>
>> How do I put a literal string in the
>> target of a regex?
>>
>> Many thanks,
>> -T

On 10/29/22 13:07, Elizabeth Mattijsen wrote:
 > $ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)'
 >

Hi Elizabeth,

Thank you for the subst workaround!

Do you also know how to do a literal string in
the target of the regex?

-T

• how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users