Re: how do I do a literal string in the target of a regex?

$ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)'

> On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users <perl6-users@perl.org> wrote:
> 
> Hi All,
> 
> I am trying to change
> 
>     /
> 
> into
> 
>     \\\
> 
> This works:
> 
> 
> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\\\\\|;print $x ~ "\n"'
> a\\\b\\\c\\\d
> 
> 
> But this does not:
> 
> $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|Q[\\\]|;print $x ~ "\n"'
> aQ[\]bQ[\]cQ[\]d
> 
> 
> How do I put a literal string in the
> target of a regex?
> 
> Many thanks,
> -T

• how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users
• Re: how do I do a literal string in the target of a regex? by Elizabeth Mattijsen
• Re: how do I do a literal string in the target of a regex? by ToddAndMargo via perl6-users