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Re: Easier way to load a buffer?

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From:
Elizabeth Mattijsen
Date:
June 10, 2022 22:28
Subject:
Re: Easier way to load a buffer?
Message ID:
CADBCE50-85BE-4CCA-AFB6-2CAF998AF85D@dijkmat.nl


> On 10 Jun 2022, at 23:28, ToddAndMargo via perl6-users <perl6-users@perl.org> wrote:
> 
>>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users <perl6-users@perl.org <mailto:perl6-users@perl.org>> wrote:
>>>    Hi All,
>>>    I am looking for an easier way to load a buffer.
>>>    I know about this way
>>>    [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53);
>>>    Buf:0x<2A 54 FF 53>
>>>    I would like to do it on one big blast:
>>>    my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78);
>>>    Cannot unbox 170 bit wide bigint into native integer
>>>    But do not know the proper syntax.
>>>    Any words of wisdom?  Am I stuck with the hard way?
>>>    Many thanks,
>>>    -T
> 
> On 6/10/22 08:36, Simon Proctor wrote:
>> So Buf is expecting a list of integers. If' you've got one long one in a string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split it into smaller values so something like this?
>> my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78";
>> my Buf $b=Buf.new(comb(2).map( *.parse-base(16) ));
>> Which does the trick I think.
> 
> 
> [0] > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78";
> 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78
> [1] > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) ));
> ===SORRY!=== Error while compiling:
> Calling comb(Int) will never work with signature of the proto ($, $, $?, *%)
> ------> my Buf $b=Buf.new(⏏comb(2).map( *.parse-base(16) ));
> [1] >

You could think: what does "comb(2)" do?  Perhaps look at the documentation?  And then maybe realize that Simon forgot that the comb(2) should be a method on $hex?  Otherwise, how would it know what to parse?

I know it is hard to think when you're in a hurry.  But you should really learn to be able to read code, instead of copying examples only and not understanding *how* they work.
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