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Postings from June 2022
>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users >> <perl6-users@perl.org <mailto:perl6-users@perl.org>> wrote: >> >> Hi All, >> >> I am looking for an easier way to load a buffer. >> >> I know about this way >> >> [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); >> Buf:0x<2A 54 FF 53> >> >> I would like to do it on one big blast: >> >> my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); >> Cannot unbox 170 bit wide bigint into native integer >> >> But do not know the proper syntax. >> >> Any words of wisdom? Am I stuck with the hard way? >> >> Many thanks, >> -T >> On 6/10/22 08:36, Simon Proctor wrote: > So Buf is expecting a list of integers. If' you've got one long one in a > string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to > split it into smaller values so something like this? > > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); > > Which does the trick I think. What does the * i *.parse-base do?Thread Previous | Thread Next