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Postings from July 2006
Darren Duncan wrote: > Assuming that all elements of $a and $b are themselves immutable to all > levels of recursion, === then does a full deep copy like eqv. If at any > level we get a mutable object, then at that point it turns into =:= (a > trivial case) and stops. ( 1, "2.0", 3 ) === ( 1,2,3 ) True or false? More imprtantly, how do I tell perl what I mean? The best I can think of is: [&&] (@a »==« @b) Vs [&&] (@a »eq« @b) But this only works for nice flat structures. For arbitrary tree structures, we probably need adverbs on a comparison op (I think Larry mentioned this a few posts back) ... but if we're going with adverbs do we really need 5 different base operators? Are all of the 5 so common that it would be clumbersome to require adverbs for their behavior? Also, when sorting things, maybe deep inequalities would be useful, too.Thread Previous | Thread Next