Damian Conway wrote: > So, to clarify again, if $var is undefined, then the assignment: > > $var op= $value; > > is equivalent to: > > $var = (&op.does(identval) ?? &op.identval() :: undef) op $value; > > Correct? Might I add that it should read $var = (&op.does(identval) ?? &op.identval($value) :: undef) op $value; The rational is, that &op is subject to MMD, so the .identval method should be dispatched as well. Actually &op.identity($value) reads quite natural and self documenting if the parameter is required. Hmm, the MMD form identity( &op, $value ) looks even better. This folds the identity value selection problem back into type-space and it's runtime agent MMD. -- TSa (Thomas Sandlaß)Thread Previous | Thread Next