Re: (\@a) = \($x,$y) in non-void context

Dave Mitchell wrote:
> In the current implementation the first two cases are equivalent;
> however, in the last (lval) case they differ; with this:
> 
>     \(@a) = \($a, $b);  \(@a) = \($c, $d);
> 
> @a[0,1] are left aliased to $c and $d, as you'd expect; with this:
> 
>     (\(@a) = \($a, $b)) = \($c, $d);
> 
> @a[0,1] are left aliased to $a and $b.

I would consider that a bug.

• (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by Aristotle Pagaltzis
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by David Nicol
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by David Nicol
• Re: (\@a) = \($x,$y) in non-void context by Aristotle Pagaltzis
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by Aristotle Pagaltzis
• Re: (\@a) = \($x,$y) in non-void context by David Nicol
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by Father Chrysostomos
• Re: (\@a) = \($x,$y) in non-void context by Dave Mitchell
• Re: (\@a) = \($x,$y) in non-void context by H.Merijn Brand
• Re: (\@a) = \($x,$y) in non-void context by Father Chrysostomos
• Re: (\@a) = \($x,$y) in non-void context by David Nicol
• Re: (\@a) = \($x,$y) in non-void context by Aristotle Pagaltzis