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Postings from July 2016
This works:
sub foo {
my $x = shift;
return $x * 2;
}
my $r = foo 5;
print $r;
You can call foo without the explicit (). But one place where you can't omit
the brackets is inside the body of foo itself.
sub foo {
my $x = shift;
if ($x == 0) { return 0 }
--$x;
return 2 + foo $x; # fails - taken as object method
}
my $r = foo 5;
print $r;
You can resolve this by adding a forward declaration:
sub foo;
sub foo {
...
But this seems un-Perlish. Could lookup rules be tweaked so that a subroutine
can make recursive calls without needing explicit parentheses or a forward
declaration?
I think it is fair enough that if a subroutine hasn't been mentioned yet
then you have to use the explicit () to call it, but this is a bit
surprising inside the body of the subroutine itself.
--
Ed Avis <eda@waniasset.com>
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