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Postings from March 2014
Aristotle Pagaltzis <pagaltzis <at> gmx.de> writes:
>>you can start
>>out with a working program, comment out lines of code one at a time,
>>and then arrive at a syntax error when the number of statements in the
>>block reaches 0.
>
>But similar cases exist for hash construction. As long as the syntax is
>ambiguous you can only trade some surprising cases in the block case for
>some surprising cases in the hash case,
But the syntax is not ambiguous. In C<{} sub foo {}> there can be no
doubt that the first {} is a code block and not a hash constructor.
If you try taking it as a hash constructor you get a syntax error.
The problem is that Perl's parser jumps one way based on a heuristic and
then isn't smart enough to try the other possibility.
--
Ed Avis <eda@waniasset.com>
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