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Re: Perlfunc for each(), keys(), values() has been changed

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March 30, 2013 17:07
Re: Perlfunc for each(), keys(), values() has been changed
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On 29 March 2013 18:10, Lukas Mai <> wrote:
> On 29.03.2013 18:06, Aristotle Pagaltzis wrote:
>> So how about this? Or something along these lines.
>>      Entries in a hash have a repeatable but arbitrary order. Therefore
>>      the order in which they are returned from C<keys>, C<values> and
>>      C<each> will match. Adding or deleting any keys changes this order
>>      arbitrarily and irreversibly, and you should expect the same set of
>>      keys in different hashes (or even in the same hash after adding and
>>      deleting keys) to yield a different order of entries. A special
>>      exception to this is made to allow you to safely delete keys from
>>      a hash while iterating over it: the entry most recently returned
>>      from C<each> or C<keys> can be deleted without changing the order of
>>      the other entries.
> This bit ("or C<keys>") makes no sense: 'keys' always returns a complete
> snapshot of the current keys. What does it mean for a key to be most
> recently returned from 'keys'?

On reflecting on this more I think you are right. The definition
should leave out keys(). Thanks.

> Besides, code like 'for (keys %foo)' isn't iterating over a hash; it's
> iterating over the list returned by 'keys', and in the loop body you can
> modify %foo however you want.

Again thinking about this more, imagine a situation where we can flag
a hash as being used for a

for my $key (keys %hash) {

type traversal. we could hypothetically start the traverse using each.
If during the traverse they inserted into the hash we could intercept
the modification and push the remaining keys onto the stack before
their modification was applied. Code that didnt modify the hash might
see a nice speed/space improvement.


perl -Mre=debug -e "/just|another|perl|hacker/"

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