[perl #85976] The 'do' function does not clear $! if it fails to compile it's argument

The documentation currently states:

  Always check $@ first, as compilation could fail in a way that also
sets $!.

Is this sufficient? I don't think we really want to be messing with the
semantics of $! in just this specific case.

-doy


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via perlbug:  queue: perl5 status: open
https://rt.perl.org:443/rt3/Ticket/Display.html?id=85976

• [perl #85976] The 'do' function does not clear $! if it fails to compile it's argument by Jesse Luehrs via RT
• [perl #85976] The 'do' function does not clear $! if it fails to compile it's argument by James E Keenan via RT
• Re: [perl #85976] The 'do' function does not clear $! if it fails tocompile it's argument by David Golden