* Dave Mitchell <davem@iabyn.com> [2011-12-06T15:41:29] > { my $x = 1; $r = qr/(??{$x})/ } > my $x = 2; > print "ok\n" if "1" =~ /^$r$/; Thanks for the report! I've been watching the (??{...}) work with interest. It's been marked experimental for ages, in part (I have assumed) because of its general twitchiness. I've been wondering whether it will soon-ish be ready to be a stable, non-experimental feature. -- rjbsThread Previous | Thread Next