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Postings from July 2010
On Thu, Jul 15, 2010 at 11:51 AM, Eric Brine <ikegami@adaelis.com> wrote:
> Functions calls are not on the precedence table. They are considered terms
> (not operators) at the grammar level.
From perlop:
Terms and List Operators (Leftward)
A TERM has the highest precedence in Perl. They include variables,
quote and quote-like operators, any expression in parentheses, and any
function whose arguments are parenthesized. Actually, there aren't
really functions in this sense, just list operators and unary operators
behaving as functions because you put parentheses around the arguments.
These are all documented in perlfunc.
Thus it seems clear that functions get evaluated first.
Maybe it's even more direct. Given:
f() . g()
The first thing encountered is a "function operation" on f, which must
be evaluated before a concatenation. Then:
$result . g()
The function operation on g has higher precedence and is evaluated.
Then the concatenation is evaluated. This is analogous to:
1 * 2 + 3 * 4
So, as written, it sounds to me like f() should happen before g().
-- David
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