On Wed, Jul 15, 2009 at 12:13 PM, Eric Brine<ikegami@adaelis.com> wrote: > The only between that and my original post is that I combined > > my $copy = $buf; > $buf := $copy; > > into > > $buf := my $copy = $buf; so is := clearer than "lvalue reference syntax?" In LRS, that would be my $copy = $buf; \$buf = \$copy; into \$buf = \(my $copy = $buf); I don't know how small of a minority I am in, but LRS doesn't require a new syntax signifier that looks like other things. When I see "$buf := $copy" my inclination is to track down a recent reference card and see what the colon operator does, because I mentally unfold that construction to "$buf = $buf : $copy" which presumably means to add whatever attribute is represented by $copy to the $buf variable.Thread Next