Using %^H in Perl 5.8.x?

G'day p5p,

My understanding is that %^H is considered stable in Perl 5.10, but I can't 
hope but notice that %^H also exists in 5.8, but is marked as experimental.

* Am I correct that %^H in 5.8 works the same as %^H in 5.10?

* Can I assume that %^H will no longer be considered experimental
   in 5.8.9 ?

* Are there any gotchas with regards to %^H in 5.8 that don't
   exist in 5.10?

I'd love to have a release of autodie[1] that works in 5.8, but I can only 
do this if I can depend upon a working %^H.

Many thanks,

	Paul

[1] Apologies for the lack of updates.  I woke up one day having realised 
that I'd spent more than one week in the same city and it's taken me a while 
to recover from the shock.

-- 
Paul Fenwick <pjf@perltraining.com.au> | http://perltraining.com.au/
Director of Training                   | Ph:  +61 3 9354 6001
Perl Training Australia                | Fax: +61 3 9354 2681

• Using %^H in Perl 5.8.x? by Paul Fenwick
• Re: Using %^H in Perl 5.8.x? by Nicholas Clark