Re: my $x->{foo} doesn't work

On Fri, May 21, 2004 at 10:47:54AM +0200, Rafael Garcia-Suarez wrote:
> Your patch looks correct at a first glance, but I'm not very inclined to
> apply it, unless the crowd comes up with good reasons why to.

The patch incorrectly removes introduction:

    for (1..4) {
	(my $x)->{foo} = 1;
	print "$_: already exists!!\n" if exists $x->{bar};
	$x->{bar} = 1;
    }

with the patch outputs:

    2: already exists!!
    3: already exists!!
    4: already exists!!


-- 
The Enterprise is captured by a vastly superior alien intelligence which
does not put them on trial.
    -- Things That Never Happen in "Star Trek" #10

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• Re: my $x->{foo} doesn't work by Rafael Garcia-Suarez
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• Re: ++(my $x = {}) [Was: Re: my $x->{foo} doesn't work] by Ronald J Kimball
• Re: ++(my $x = {}) [Was: Re: my $x->{foo} doesn't work] by Dan Kogai
• Re: my $x->{foo} doesn't work by Shinya Hayakawa
• Re: my $x->{foo} doesn't work by Elizabeth Mattijsen
• Re: my $x->{foo} doesn't work by Dave Mitchell
• Re: my $x->{foo} doesn't work by Rafael Garcia-Suarez
• Re: my $x->{foo} doesn't work by Dave Mitchell
• Re: my $x->{foo} doesn't work by Shinya Hayakawa
• Re: my $x->{foo} doesn't work by hv
• Re: my $x->{foo} doesn't work by Shinya Hayakawa
• Re: my $x->{foo} doesn't work by Dave Mitchell
• Re: my $x->{foo} doesn't work by Rafael Garcia-Suarez