open(1, <filename>) ?

I was expecting the following code snippet to give an
error (something like 1st arg. not a glob).

% perl5.8.2 -e 'open(1, ">tst") || die "error - $!\n";
print STDOUT "test\n";'
test
%

strace() shows that perl indeed calls open() - any
idea what happens to the returned handle ? Obviously
print 1 "test\n" won't work - so the above form should
be an error ?
(ofcourse, I didn't expect print STDOUT to print to
tst)

Sreeji

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• open(1, <filename>) ? by Sreeji K Das
• Re: open(1, <filename>) ? by Sreeji K Das
• Re: open(1, <filename>) ? by Autrijus Tang