http://rt.perl.org/rt2/Ticket/Display.html?id=8634 I've read through the thread and complex maze of patches proposed to resolve this bug. The following is what I've come up with. Casey West -- Shooting yourself in the foot with APL @#&^$%&%^ foot --- perl-current.orig/pod/perlop.pod Mon Apr 28 13:44:51 2003 +++ perl-current/pod/perlop.pod Fri May 9 05:19:29 2003 @@ -458,15 +458,29 @@ doesn't affect its numeric value, but gives you something to search for if you want to exclude the endpoint. You can exclude the beginning point by waiting for the sequence number to be greater -than 1. If either operand of scalar ".." is a constant expression, -that operand is implicitly compared to the C<$.> variable, the -current line number. Examples: +than 1. + +If either operand of scalar ".." is a constant expression, +that operand is considered true if it is equal (C<==>) to the current +line number (the C<$.> variable). + +To be pedantic, the comparison is actually C<int(EXPR) == int(EXPR)>, +but that is only an issue if you use a floating point expression or +C<$.> is set to a floating point value without reading from a file. +Furthermore, C<"span" .. "spat"> or C<2.18 .. 3.14> will not do what +you want in scalar context because each of the operands are evaluated +using their integer representation. + +Examples: As a scalar operator: - if (101 .. 200) { print; } # print 2nd hundred lines - next line if (1 .. /^$/); # skip header lines - s/^/> / if (/^$/ .. eof()); # quote body + if (101 .. 200) { print; } # print 2nd hundred lines, short for + # if ($. == 101 .. $. == 200) ... + next line if (1 .. /^$/); # skip header lines, short for + # ... if ($. == 1 .. /^$/); + s/^/> / if (/^$/ .. eof()); # quote body, short for + # ... if (/^$/ .. $. == eof()); # parse mail messages while (<>) { @@ -474,7 +488,7 @@ $in_body = /^$/ .. eof(); # do something based on those } continue { - close ARGV if eof; # reset $. each file + close ARGV if eof; # reset $. each file } As a list operator: @@ -501,6 +515,11 @@ in the sequence that the magical increment would produce, the sequence goes until the next value would be longer than the final value specified. + +Because each operand is evaluated in integer form, C<2.18 .. 3.14> will +return two elements in list context. + + @list = (2.18 .. 3.14); # same as @list = (2 .. 3); =head2 Conditional OperatorThread Next