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Re: [perl #19750] is you or is you ain't an operator?

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From:
Andy Lester
Date:
April 24, 2003 13:30
Subject:
Re: [perl #19750] is you or is you ain't an operator?
Message ID:
20030424202229.GC29642@petdance.com
> So if you feel this way then there should be an entry in L<perlop>
> that says "there are really functiony operators, look in L<perlfunc>"?
> (I don't mind this idea either.)

Either that, or combine them.

Imagine I'm a user and I see this "tr" thing.  I'll probably look in
perlfunc, right?  It's not, of course.



-- 
'Andy Lester        andy@petdance.com
 Programmer/author  petdance.com
 Daddy              parsley.org/quinn   Jk'=~/.+/s;print((split//,$&)
                            [unpack'C*',"n2]3%+>\"34.'%&.'^%4+!o.'"])

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