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Re: [perl #19750] is you or is you ain't an operator?

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Andy Lester
April 24, 2003 13:30
Re: [perl #19750] is you or is you ain't an operator?
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> So if you feel this way then there should be an entry in L<perlop>
> that says "there are really functiony operators, look in L<perlfunc>"?
> (I don't mind this idea either.)

Either that, or combine them.

Imagine I'm a user and I see this "tr" thing.  I'll probably look in
perlfunc, right?  It's not, of course.

'Andy Lester
 Daddy       Jk'=~/.+/s;print((split//,$&)

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