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Postings from February 2003
Dunno where this 'from' line came from, but it says here: perl5-porters-return-71692-hv=crypt.org@perl.org wrote: :On Sun, Jan 12, 2003 at 10:24:23AM +0100, Leopold Toetsch wrote: :all default to a machine dependent default. This default isn't documented :explicitly, but I presume that on x86 it's the same as the x86 specific -m :options of the same name (deprecated in gcc 3.0, removed along with their :documentation by 3.2) : :*Their* alignment defaults are: : :`-malign-loops=NUM' : Align loops to a 2 raised to a NUM byte boundary. If : `-malign-loops' is not specified, the default is 2 unless gas 2.8 : (or later) is being used in which case the default is to align the : loop on a 16 byte boundary if it is less than 8 bytes away. : :sooooo : :50% of the time your function/label/loop/jump is 16 byte aligned. :50% of the time your function/label/loop/jump is "randomly" aligned I read this differently: 16n+7 should be aligned to 16n, because it is less than 8 bytes away; 16n+9 should be aligned 16n+16 similarly. Only 16n+8 would be unaligned, so that only in 1/16 random cases would it fail to be 16-byte aligned, and then it would still be 8-byte aligned. That doesn't necessarily invalidate any of the rest of what was said. HugoThread Previous | Thread Next