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Postings from June 2001
On Tue, Jun 12, 2001 at 01:14:15PM +0100, Mike Guy wrote:
> Robin Barker <rmb1@cise.npl.co.uk> wrote
> > You probably want to replace @@ by \@\@,
> > as (I think) @@ will include array @.
>
> No, actually. "Punctuation" arrays aren't interpolated in doublequotish
> strings. A fact that doesn't seem to be documented.
>
> In fact, how arrays interpolate isn't documented at all (except
> implicitly in the description of $" in perlvar).
> --- ./pod/perlop.pod.orig Sun May 6 15:24:51 2001
> +++ ./pod/perlop.pod Tue Jun 12 13:10:01 2001
> @@ -733,6 +735,15 @@
> and although they often accept just C<"\012">, they seldom tolerate just
> C<"\015">. If you get in the habit of using C<"\n"> for networking,
> you may be burned some day.
> +
> +Subscripted variables such as C<$a[3]> or C<$href->{key}[0]> are also
> +interpolated, as are array and hash slices. But method calls
> +such as C<$obj->meth> are not interpolated.
> +
> +Interpolating an array or slice interpolates the elements in order,
> +separated by the value of C<$">, so is equivalent to interpolating
> +C<join $", @array>. "Punctuation" arrays such C<@+> are not
> +interpolated.
s/such/such as/;
However, a little earlier in the doc, around line 695, is the sentence:
For constructs that do interpolate, variables beginning with "C<$>"
or "C<@>" are interpolated, as are the following escape sequences.
And there's also this bit, just after your new text:
> You cannot include a literal C<$> or C<@> within a C<\Q> sequence.
> An unescaped C<$> or C<@> interpolates the corresponding variable,
The section on interpolation may be a bit disorganized right now.
Ronald
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