Simon Cozens writes: > Hence, it would be a net pessimisation for a questionable gain. Plus > it defines a semantic, removing a degree of optimisation freedom. Those who think that (++$i, ++$i) should work would quote MjD at this point: "you don't care whether it's correct or not? In that case, I can make it REALLY fast! return 0" Ahem. :-) NatThread Previous | Thread Next