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Postings from November 2000
> OK. What does a scalar with IV and NV both OK mean?
I *think* it *should* mean that the cached IV and NV are both valid
*and* that there is no loss of precision: (IV)nv == iv && (NV)iv == nv.
Obviously, this doesn't seem to be the case.
> And what are the private flags actually used form?
No idea, sorry.
> There seems to be an implicit assumption that NV preserves IV always,
Yes, an unfortunate assumption. I've tried shaking it once in a while
but too many tests have started failing (numconvert, it nothing else)
so I have always backed up.
> Am I right in thinking this is going to mean changing the 2nv and 2iv and 2uv
> code in sv.c?
Sounds familiar.
--
$jhi++; # http://www.iki.fi/jhi/
# There is this special biologist word we use for 'stable'.
# It is 'dead'. -- Jack Cohen
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