Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions

Graham Barr <gbarr@dhcp69.uk.valueclick.com> wrote
> During the change to make qw() compile time the interpretation of
> the contents seems to have changed too.
> 
$ perl5.00503 -le 'print qw{ (?:\\\\.|[^\\\\()]+)* }'
> (?:\\.|[^\\()]+)*
> 
> $ perl5.6.0  -le 'print qw{ (?:\\\\.|[^\\\\()]+)* }'
> (?:\\\\.|[^\\\\()]+)*  

Clearly a bug, since both 5.005_03 and 5.6.0, in their own ways, say that
the argument to qw{} is subject to q{} quoting:

--------------  5.005_03 ----------------------
             It is exactly equivalent to

                 split(' ', q/STRING/);
-----------------------------------------------

--------------  5.6.0    ----------------------
                          It can be understood as being roughly
             equivalent to:

                 split(' ', q/STRING/);

             the difference being that it generates a real list
             at compile time.  So this expression:

                 qw(foo bar baz)

             is semantically equivalent to the list:

                 'foo', 'bar', 'baz'
-----------------------------------------------


Neither quote is entirely honest with respect to delimiters, but I
guess it's near enough.


Mike Guy

• [ID 20000411.002] qw() gives different results in 5.6 to previousversions by Graham Barr
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by M.J.T. Guy
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Gurusamy Sarathy
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Tom Hughes
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previousversions by Jeff Pinyan
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Graham Barr