Re: [ID 20000411.002] qw() gives different results in 5.6 to previousversions

>During the change to make qw() compile time the interpretation of
>the contents seems to have changed too.

>$ perl5.00503 -le 'print qw{ (?:\\\\.|[^\\\\()]+)* }'
>(?:\\.|[^\\()]+)*

>$ perl5.6.0  -le 'print qw{ (?:\\\\.|[^\\\\()]+)* }'
>(?:\\\\.|[^\\\\()]+)*  

Whoa.  So instead of just being a compile-time list, you get TRUE
single-quoted context?  Have you tried doing

  qw( this \) that )

I'm just curious because the only other place you can get 0 interpolation
like that is in a single-quoted here-document.

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• [ID 20000411.002] qw() gives different results in 5.6 to previousversions by Graham Barr
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by M.J.T. Guy
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Gurusamy Sarathy
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Tom Hughes
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previousversions by Jeff Pinyan
• Re: [ID 20000411.002] qw() gives different results in 5.6 to previous versions by Graham Barr