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Postings from November 1999
On Fri, 26 Nov 1999, Ilya Zakharevich wrote: > On Thu, Nov 25, 1999 at 04:55:59AM -0500, Philip Newton wrote: > > Something along the lines of having \-conversion > > (\n \f etc.) done in parallel with \c-conversion, and having \c\ do > > roughly the same thing as \c if the following character is either a > > backslash or the closing delimiter, e.g. "\c\\", "\c\"", qq^\c\^^. > > you are missing the *most important* point again: closing " is found first. Yes, but according to perlop/Gory Details, while searching for the closing " of "" (or closing ^ of qq^^, etc.), the combinations \\ and \" (or \^, etc.) are skipped. Hence, according to my understanding, "\c\\" (after the first "pass", finding the end) turns into >>\c\\ inside ""<<; "\c\"" into >>\c\" inside ""<<; and qq^\c\^^ into >>\c\^ inside qq^^<<. After this, backslash+delimiter are turned into plain delimiter (while backslash+backslash is kept), and knowledge of the original delimiter is lost, so the three strings become \c\\, \c" and \c^, respectively. Hmmm, I think I begin to understand. No change is needed for control-(closing delimiter), since the interpolation step doesn't see backslashes there any more. However, I still believe that handling of \c\\ should be changed to produce ctrl-\ instead of ctrl-\, \. Cheers, Philip -- Philip Newton <newton@newton.digitalspace.net>Thread Previous | Thread Next