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RE: even.pl solutions
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From:
Dave Hoover
Date:
January 28, 2002 20:08
Subject:
RE: even.pl solutions
Message ID:
NFBBLBJAALMELNDMDOFCEEMOCDAA.dave@redsquirreldesign.com
Rick Myers wrote:
>On Jan 28, 2002 at 19:56:05 -0600, Dave Hoover wrote:
>> Can someone explain to my poor ignorant head what "low-order bit" means?
>> I'm guessing it has something to do with the '&' operator. Be gentle.
>
>Simple. As each requirement for this hole was supposed to be
>"even", it had to be a multiple of two. Thus, in binary
>terms, the "low-order-bit" would always be zero.
>
>Of course though, if you don't grok binary, that probably
>doesn't make any sense.
push @things_to_learn, 'binary';
Thanks for trying,
--Dave
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