if structure voiding string when condition not met?

When I run this code

&buildexcel("Age");
...
sub buildexcel{
    ...
    my $sheet=$book->worksheets('AgeRaw') if ($_[0] eq "Age");
    my $sheet=$book->worksheets('ReceiptsRaw') if ($_[0] eq "Cash");
    $sheet->activate();
    ...
}

I get this error
...
Can't call method "activate" on an undefined value at armonth.pl line 92
<AGE> line 17904.

If I comment out
my $sheet=$book->worksheets('ReceiptsRaw') if ($_[0] eq "Cash");
then it executes correctly.

This is really confusing me since the only thing being passed to the
subroutine is "Age" so the "Cash" if should never ever execute. But it
seems that it is checking it and then setting $sheet to null or
something when the condition comes back false.

I am 
Paul Kraus
Network Administrator
PEL Supply Company
216.267.5775 Voice
216-267-6176 Fax
www.pelsupply.com

• if structure voiding string when condition not met? by Paul Kraus
• RE: if structure voiding string when condition not met? by Ed Christian
• Re: if structure voiding string when condition not met? by Rob Dixon
• Re: if structure voiding string when condition not met? by Paul Johnson