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Re: Debugging and 'uninitialized value in concatenation' question

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Jenda Krynicky
April 25, 2002 13:17
Re: Debugging and 'uninitialized value in concatenation' question
Message ID:
From: "Jason Frisvold" <>
> Judging from the subject lines coming across the list today, I think
> I'm gonna toss this question out there and then duck and cover...  :-)

We do not shoot at people here. Even if they do provide the missile 
address. ;-)
> Question #1.
> When I'm writing code, I want to be able to view as much output as
> possible so I can trace through everything and ensure that it is,
> indeed, running correctly.  I've gone as far as writing my own debug
> module that uses "levels" and outputs everything in color.
> (Term::ANSIColor is a lot of fun to play with)...  One major side
> effect of this is that my code will begin to run slower due to all of
> the debugging...
> So, the obvious answer is to turn off the debugging.  However, even
> with my magic "debug off switch" (see below for a better explanation),
> the calls to the debug routines are still being made.  Is there any
> sort of #IFDEF that can be done in perl, or do I actually have to
> comment out (or remove) each call?
> My magic "debug off switch" is nothing more than a simple if/then
> statement.  It works on the principle that if $IDebugLevel is a
> positive integer greater than 0, then I want to debug.

You may mark them somehow and then process your script with 
something that'll comment them out or strip them entirely.


> Question #2.
> Relating to the debugging, there are several instances where I have
> variables that are only defined based on the definition of other
> variables that exist elsewhere.  Kind of like :
> sub dummy {
> if ($a == 10) { my $b = 0; }
> }
> $b is a local variable, so whenever the subroutine is exited, $b
> vanishes into the ether.  

In this case the difference is not visible, but still ... please keep in 
mind that the scope of a variable is a block, not a subroutine!

	sub foo {
		if (1 > 2) {
			my $x = 1;
		print "\$x=$x\n";
will NOT print

I hope you DO
	use strict;

> The problem is that I have $b in several
> debug statements because I want to see it when it's used, but I don't
> want to have to create a huge if/then structure to determine what
> variables are being used.

No you cannot acces a lexical variable (declared with my()) outside 
its scope. The only kind-of exception are closures ... subroutines 
defines inside the variable's scope and thus able to access it later. 
But that's not what you want.

=========== == ==========
There is a reason for living. There must be. I've seen it somewhere.
It's just that in the mess on my table ... and in my brain
I can't find it.
					--- me

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