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RE: how to sort, in to out

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From:
David Gray
Date:
March 21, 2002 06:41
Subject:
RE: how to sort, in to out
Message ID:
000f01c1d0e6$5e214a20$7800a8c0@3b2.com
> >> I am trying to figure out an easy way to sort out a array 
> of numbers: 
> >> 2 20 38 56 75 93 -17 -35 -53 -72 -90 Into the following:
> >> -90 -72 -53 -35 -17 2 20 38 56 75 93
> >> I have done the following:
> >>   @x_step  = grep { ! $x_step_t{ $_ }  ++ } @x_step_t;
> >>   @x_step = sort {$a == $b} @x_step;
> > 
> > You're really close:
> > 
> > @x_step = reverse sort {$a<=>$b} @x_step;
> > 
> > -dave
> 
> I thought of that right away too. But, wouldn't it produce 
> the wrong array? -90 -72 -53 -35 -17 93 75 56 38 20 2?

Jenda is right :) try it out, it should be what you need.

 -dave



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