develooper Front page | perl.beginners | Postings from March 2002

Re: how to sort, in to out

Thread Previous | Thread Next
From:
Tor Hildrum
Date:
March 21, 2002 06:36
Subject:
Re: how to sort, in to out
Message ID:
B8BFAE81.6F0E%torhildr@mac.com
On 21/3/02 15:04, "David Gray" <david_gray@3b2.com> wrote:

>> I am trying to figure out an easy way to sort out a array of numbers:
>> 2 20 38 56 75 93 -17 -35 -53 -72 -90
>> Into the following:
>> -90 -72 -53 -35 -17 2 20 38 56 75 93
>> I have done the following:
>>   @x_step  = grep { ! $x_step_t{ $_ }  ++ } @x_step_t;
>>   @x_step = sort {$a == $b} @x_step;
> 
> You're really close:
> 
> @x_step = reverse sort {$a<=>$b} @x_step;
> 
> -dave

I thought of that right away too. But, wouldn't it produce the wrong array?
-90 -72 -53 -35 -17 93 75 56 38 20 2?

-- 
T.



Thread Previous | Thread Next


nntp.perl.org: Perl Programming lists via nntp and http.
Comments to Ask Bjørn Hansen at ask@perl.org | Group listing | About