develooper Front page | perl.beginners | Postings from March 2002

RE: how to sort, in to out

Thread Previous | Thread Next
From:
David Gray
Date:
March 21, 2002 06:05
Subject:
RE: how to sort, in to out
Message ID:
000e01c1d0e1$451d1f40$7800a8c0@3b2.com
> I am trying to figure out an easy way to sort out a array of numbers:
> 2 20 38 56 75 93 -17 -35 -53 -72 -90
> Into the following:
> -90 -72 -53 -35 -17 2 20 38 56 75 93
> I have done the following:
>   @x_step  = grep { ! $x_step_t{ $_ }  ++ } @x_step_t;
>   @x_step = sort {$a == $b} @x_step;

You're really close:

@x_step = reverse sort {$a<=>$b} @x_step;

 -dave



Thread Previous | Thread Next


nntp.perl.org: Perl Programming lists via nntp and http.
Comments to Ask Bjørn Hansen at ask@perl.org | Group listing | About