Front page | perl.beginners |
Postings from February 2002
> The trick is to use {$ref} where you would normally put the variable name:
print "${$rhash}{1}\n"; worked like a charm :)
> So $array[0] becomes ${$ref}[0] (not @$ref[0] which is a "slice").
> And $hash{key} becomes ${ref}{key}.
It seems somewhat inconsistent to me.
While I can dereference slices from $variables and @arrays this way, I can't
from a %hash? (using $$name, @$name[] and %$name{}).
Maybe it's my lack of understanding hash'es..
> Or you can use the little arrow syntax...
>
> ${$ref}[0] is the same as $ref->[0].
> And ${$ref}{key} is the same as $ref->{key}.
Yes, this looks like the way to go. Much easier and clearer than the
previous syntax.
${$rhash}{1} == $rhash->{1}; ## both are scalar variables, not slices?
> In your script you are doing a variation of the first, where you are just
> dropping the curly braces. In which case it would look like this:
>
> ${$ref}[0] is the same as $$ref[0] (NOT @$ref[0]).
> ${ref}{key} is the same as $$ref{key}.
>
> Hope that helps. Check out the perlreftut manpage, it explains all of this
> pretty well while avoiding all of the nasty details of refs.
Thanks. :)
--
T.
Thread Previous