Andy_Bach-at-wiwb.uscourts.gov |Perl 6| wrote: > in. Er, so would: > my CGI::Simple $x .= new; > my $y = CGI::Simple.new; > > mean that: > $x <whatever the compare class operater is> $y > > is not true? Or would there be a way to tell them apart, on a class (?) > level. > > The actual dynamic type at run time of the values in $x and $y are both CGI::Simple. The static compile-time type of $y is Any. $x.nosuchmethod; will give a compile-time error if nosuchmethod is not declared as part of CGI::Simple. $y.nosuchmethod; will look it up when the attempt is made, and only then fail. (Or succeed if something funny is going on and it exists =now= but wasn't declared originally. There are a few documented ways to be funny already.)Thread Previous | Thread Next