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Postings from May 2007
Andrew Shitov:
> If the line of code is not ended with ';' the parser tries first
> to assume [..]
Wouldn't that be unambigous?
foo = 23
bar = \
42
?
I think there would be no ambiguities and you only had to add additional
syntax for the rare cases instead of the common cases.
--
Thomas Wittek
http://gedankenkonstrukt.de/
Jabber: streawkceur@jabber.i-pobox.net
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