Re: @array = $scalar

I think this deserves at least a compile time warning and also a strict pragma to make it an error as it is most likely not what the programmer wanted.

--
Mark Biggar
mark@biggar.org
mark.a.biggar@comcast.net
mbiggar@paypal.com


> Ingo Blechschmidt skribis 2005-08-31 13:22 (+0000):
> >     @array = $arrayref;                  # really means 
> >     @array = ($arrayref,);               # same as 
> >     @array = (); @array[0] = $arrayref;  # thus 
> >     say +@array;                         # always 1 
> >     # Correct? 
> 
> Yes, although at some point there was this weird notion of scalars
> automatically dereferencing in list context, in this respect Perl 6
> currently is sane.
> 
> 
> Juerd
> -- 
> http://convolution.nl/maak_juerd_blij.html
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• @array = $scalar by Ingo Blechschmidt
• Re: @array = $scalar by mark.a.biggar
• Re: @array = $scalar by Juerd
• Re: @array = $scalar by Ashley Winters
• Re: @array = $scalar by Juerd
• Re: @array = $scalar by Damian Conway
• Re: @array = $scalar by Stuart Cook
• Re: @array = $scalar by Juerd
• Re: @array = $scalar by Juerd