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Postings from April 2003
Paul wrote: > --- Austin Hastings <austin_hastings@yahoo.com> wrote: > >>--- Paul <ydbxmhc@yahoo.com> wrote: >> >>> $x = @y; # $x now a handle on @y >>> $x[0]++; # increments @y[0] >> >>I think it's C<:=> to do an explicit reference binding. >> >> $x := @y; # Note ':' >> >>I'm not clear on what C<$x = @y;> will do, It will assign \@y to $x. > I thought I saw somewhere that an array would automatically yield a > reference in that context, for some definition of "that", but you're > right, it seems more likely that it'd just give the length. Nope. A reference. Length is only yielded in numeric context. Which this isn't. >>>I suspect that you could say >>> >>> my Int $i = 1; >>> print $i; # all types *do* stringify, don't they? No. Junctive types don't. > my Int $i = 3; > my Str $s = $i; # should be a no-no Okay, I suspect. Automatic conversion. > > I'd expect > > $i ~~ "123" > > to fail, depending on smart-matching semantics, It fails because $i contains 3. The smart-match: $i ~~ "3" would match. but > > $s = "$i"; # quotes implicitly stringify > > to succeed.... No. Again, "3" doesn't match "123". Damian PS: I'd really like to respond to more of these type threads, but writing E6 is taking precedence just now. That doesn't mean that I don't find people's assumptions and confusions valuable. And I'm sure Larry does too. :-)Thread Previous | Thread Next