Front page | perl.perl6.language |
Postings from April 2002
In reply to Buddha Buck <bmbuck@14850.com>:
> At 08:58 AM 04-23-2002 -0700, Larry Wall wrote:
> >Precedence is set with the "like' property:
> >
> > my sub operator:now ($a,$b) is like("but") is inline { $a but $b
> }
> > sub operator:also ($a,$b) is like("and") is inline { $a and $b }
>
> OK, but that limits you to the, um, 24 standard levels of precedence.
> What
> do you do if you don't think that that's enough. Let's say you want to
>
> define a "nand" operator:
>
> my sub operator:nand ($a, $b) is inline { not ($a and $b) }
>
> but you want nand to have a precedence lower than the existing 'and' but
>
> higher than the existing 'or' (for some reason I can't imagine
> offhand). It isn't like() anything, since there isn't anything
> currently
> between 'and' and 'or'. Would that be something like:
>
> my sub operator:nand ($a, $b) is below("and") is inline {not ($a and $b)
> }
>
24 levels of precedence should be enough, else you can always resort to parens.
Guillaume
Thread Previous
|
Thread Next