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Re: reduce via ^
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From:
Jonathan Scott Duff
Date:
October 10, 2001 14:04
Subject:
Re: reduce via ^
Message ID:
20011010160418.H17820@cbi.tamucc.edu
On Wed, Oct 10, 2001 at 01:27:35PM -0700, Colin Meyer wrote:
> On Wed, Oct 10, 2001 at 09:42:58PM +1000, Damian Conway wrote:
> >
> > John observed:
> >
> > > I just read Apocalypse and Exegesis 3, and something stuck out at me
> > > because of its omission, namely using hyper operators for reduction.
> > >
> > > $a ^+= @list; # should sum the elements of @list
>
> Does this mean that
>
> @a ^+= @b;
>
> will add every value of @b to every value of @a?
That's what I'd expect it to do. Well ... that's assuming you really
mean "each" where you said "every". i.e.,
my $i = 0;
while ($i < length(@a) && $i < length(@b)) {
@a[$i] += @b[$i];
}
Just like I'd expect
@a = @b ^=~ @patterns;
to be roughly equivalent to:
my $i = 0; @a = ();
while ($i < length(@patterns) && $i < length(@b)) {
push @a, (@b[$i] =~ @patterns[$i]);
$i++;
}
-Scott
--
Jonathan Scott Duff
duff@cbi.tamucc.edu
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