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Postings from October 2001
Hello! Is this going to concat $a,$b and $c? $foo = _($a,$b,$c); (One way to save underlines and spaces.) Or would that be: $foo = _@($a,$b,$c); BTW: what will these do? $a _=_ ($b,$c); $a ^_= ($b,$c); # (better with hypo-operator?, see below) (WIM in Perl 5: $a .= $b.$c ?) Could there also be *hypo*-operators, i.e. operators which try to *lower* (reduce) the dimensionality of their operands to the lowest common dim. So $foo = 5 +^ (1,2); would set $foo to (5 + 1) + 2 and $foo = $a _^ ($b,$c); $a _=^ ($b,$c); would do the same concats as above respectively? Another application: $sum = 0 +^ @values; Granted: ^ is not the best choice for a meta-operator which lowers something. :) -EdwinThread Next