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Postings from July 2001
David L. Nicol wrote: > >Are there really situations where > > $$reference = An Expression; > >is clearer than > > $reference = \(An Expression); > >? Eric is confused. I don't know about in Perl 6-to-be, but in Perl 5 those two mean totally different things: $foo = \$bar; # sets $foo to be a ref to $bar $$foo = "hi mom"; # sets $bar to "hi mom" $foo = \"hi mom"; # sets $foo to be a ref to "hi mom" ---------------------------------------------------------------------- Eric J. Roode eric@myxa.com Senior Software Engineer, Myxa Corporation