On Mon, Jun 04, 2001 at 06:49:28PM -0500, Me wrote: > Afaict, even with use strict at its most strict, perl 6 > can't (in practice) complain, at compile time, if > > $foo.Foun > > refers to an undeclared Foun. > > Right? > > Should there be a strict mode that warns if a > method name matches a built in property name? Could have one that requires all inheritance and variable declarations occur at compile-time, but that will only effect your current scope. Won't help against classes you inherit from doing run-time things. And then there's autoloading... There's also the problem of knowing at compile time what class/type $foo is. Don't know what's going on with that just yet, do we? So I'd say no, Perl can't know at compile-time if your method is declared or not. Only in certain restricted cases, such as if you don't inherit from anything, or if *all* your parent classes are declared strictly. -- Michael G Schwern <schwern@pobox.com> http://www.pobox.com/~schwern/ Perl6 Quality Assurance <perl-qa@perl.org> Kwalitee Is Job OneThread Previous | Thread Next