[perl #111978] [BUG] ?^1 gives True in Rakudo

# New Ticket Created by  "Carl Mäsak" 
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# <URL: https://rt.perl.org:443/rt3/Ticket/Display.html?id=111978 >


<GlitchMr> perl6: print ?^1
<p6eval> niecza v15-6-gefda208: OUTPUT«False»
<p6eval> ..rakudo a4c78f: OUTPUT«True»
* masak submits rakudobug
<GlitchMr> "?^" operator
<benabik> r: say ^1
<p6eval> rakudo a4c78f: OUTPUT«0..^1␤»
<benabik> I think ?^1 is just ?(^1)
<GlitchMr> According to S03, it's boolean not...
<benabik> I could be wrong, I'll admit.
<GlitchMr> ... I don't mean upto operator...
<masak> benabik: there is a prefix:<?^> operator.
<masak> but it might be missing in Rakudo.

• [perl #111978] [BUG] ?^1 gives True in Rakudo by Patrick R. Michaud via RT
• [perl #111978] [BUG] ?^1 gives True in Rakudo by Carl Mäsak