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Postings from January 2012
On Sat Jan 28 13:27:55 2012, demerphq wrote:
> On 28 January 2012 19:30, Lukas Mai <l.mai@web.de> wrote:
> > On 2012-01-28 demerphq wrote:
> >
> >> You say that you consider "\n" to contain only one line.
> >>
> >> But what about "\nfoo". Does it contain one or two lines? Do you
> >> expect ^ to match after the \n in "\nfoo"? If you do then do you
> not
> >> agree there is an inconsistency about it not matching after the \n
> in
> >> "\n"?
> >
> > "\nfoo" contains 1.5 lines, i.e. one complete (but empty) line and
> one
> > incomplete (unterminated) line.
> > "\nfoo" =~ /^foo/m should match, yes.
> > I don't think there's an inconsistency because \n is only the
> beginning
> > of a line if more text follows. That is, my model of /^/m
> > is /(?:\A|(?<=\n)(?!\z))/.
>
> And the docs agree with you, perlre says this:
>
> You may, however, wish to treat a string as a multi-line buffer,
> such that
> the "^" will match after any newline within the string (except if
> the newline
> is the last character in the string), and "$" will match before any
> newline.
>
> Though I do wonder if the "except if the newline is the last
> character of the string" was a special case added later.
Which is, interestingly (but irrelevantly), the way JavaScript does it:
$ perl -MJE -le 'print new JE->eval(q|/\n^/m.test("\n")|)'true
true
(Or enter javascript:alert(/\n^/m.test("\n")) in a web browser.)
In JavaScript, /^/m is equivalent to Perl’s
/\A|(?<=[\cm\cj\x{2028}\x{2029}])/.
--
Father Chrysostomos
---
via perlbug: queue: perl5 status: open
https://rt.perl.org:443/rt3/Ticket/Display.html?id=109206
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