On Mon, Apr 12, 2010 at 03:50:52AM -0700, Alexandr Ciornii via RT wrote:
>
> On Tue Mar 28 03:39:19 2000, tchrist@chthon.perl.com wrote:
> > From a CHECK{}, you cannot exit(0). You may exit !0, but not 0.
> > If you put this in /tmp/a and run it:
> >
> > #BEGIN { warn "testing exit from BEGIN"; exit }
> > #BEGIN { warn "testing exit N from BEGIN"; exit 1 }
> >
> > #INIT { warn "testing exit from INIT"; exit }
> > #INIT { warn "testing exit N from INIT"; exit 2 }
> >
> > CHECK { warn "testing exit from CHECK"; exit }
> > #CHECK { warn "testing exit N from CHECK"; exit 3 }
> >
> > #END { warn "testing exit from END"; exit }
> > #END { warn "testing exit N from END"; exit 4 }
> >
> > print "i am now the main program\n";
> > warn "testing exit 5 from main";
> > exit 5;
> >
> > die "XXX";
> >
> > You will get:
> >
> > % perl /tmp/a
> > testing exit from CHECK at /tmp/a line 7.
> > i am now the main program
> > testing exit 5 from main at /tmp/a line 14.
> > Exit 5
> >
> > If you switch the comment on the two CHECKs, you get
> >
> > % perl /tmp/a
> > testing exit N from CHECK at /tmp/a line 8.
> > Exit 3
>
>
> Still present in 5.12.0 RC0.
And in 5.12.0-RC5 as well. However, it's not a regression for a recent
Perl. It behaves the same in 5.10.1, 5.8.[89] and 5.6.2.
It is a regression from 5.005_04 though, which will print the expected:
testing exit from CHECK at bb line 14.
Abigail
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