How to put an AND in a regex?

Hi,

I am trying to write a regex that should only match when certain patterns are not present, e.g. when a line does not start with either a digit or ALL-CAPS text. I figured I could use negative look-aheads for this.

I can write it as:

if (/^(?![[:upper:]][[:upper:]])/) {
    if (/^(?!\d)/) {
    s/^/<test>/;
    }
    else {
    }
}
else {
}

However, I was wondering whether there was a way of writing this as a single if loop, because there are much more than two situations that should not be matched.

I tried to write it as:

if (/^(?![[:upper:]][[:upper:]])|^(?!\d)/) {
s/^/<test>/;
}
else {
}

but this means if one option is not matched the other one is matched, which is not what I want. So I need something that does the equivalent of "Don't match this AND don't match this". Is this possible in a if loop, or should I use something else?

Thanks,

Regards,
Thomas Hamann

• How to put an AND in a regex? by Hamann, T.D.
• Re: How to put an AND in a regex? by C.DeRykus
• Re: How to put an AND in a regex? by Rob Dixon
• Re: How to put an AND in a regex? by John Delacour
• Re: How to put an AND in a regex? by Peter Scott
• Re: How to put an AND in a regex? by Igor Dovgiy
• RE: How to put an AND in a regex? by Hamann, T.D.