Re: Using $variable outside a foreach loop

On Jun 3, 2011, at 8:45 AM, Alan Haggai Alavi wrote:

> Here, the scope of $name is limited to the foreach loop and not outside it. 
> So, you will have to declare the variable again for use outside the loop.

	But wouldn't that make the second "$name" a different variable?  I'm not at my computer to try it.

Marc

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